Dereferencing type-punned pointer will break strict-aliasing rules

I used the following piece of code to read data from files as part of a larger program.

double data_read(FILE *stream,int code) {
        char data[8];
        switch(code) {
        case 0x08:
            return (unsigned char)fgetc(stream);
        case 0x09:
            return (signed char)fgetc(stream);
        case 0x0b:
            data[1] = fgetc(stream);
            data[0] = fgetc(stream);
            return *(short*)data;
        case 0x0c:
            for(int i=3;i>=0;i--)
                data[i] = fgetc(stream);
            return *(int*)data;
        case 0x0d:
            for(int i=3;i>=0;i--)
                data[i] = fgetc(stream);
            return *(float*)data;
        case 0x0e:
            for(int i=7;i>=0;i--)
                data[i] = fgetc(stream);
            return *(double*)data;
        }
        die("data read failed");
        return 1;
    }

Now I am told to use -O2 and I get following gcc warning: warning: dereferencing type-punned pointer will break strict-aliasing rules

Googleing I found two orthogonal answers:

• Concluding: there's no need to worry; gcc tries to be more law obedient than the actual law.

vs

• So basically if you have an int* and a float* they are not allowed to point to the same memory location. If your code does not respect this, then the compiler's optimizer will most likely break your code.

In the end I don't want to ignore the warnings. What would you recommend?

[update] I substituted the toy example with the real function.

The problem occurs because you access a char-array through a double*:

char data[8];
...
return *(double*)data;

But gcc assumes that your program will never access variables though pointers of different type. This assumption is called strict-aliasing and allows the compiler to make some optimizations:

If the compiler knows that your *(double*) can in no way overlap with data[], it's allowed to all sorts of things like reordering your code into:

return *(double*)data;
for(int i=7;i>=0;i--)
    data[i] = fgetc(stream);

The loop is most likely optimized away and you end up with just:

return *(double*)data;

Which leaves your data[] uninitialized. In this particular case the compiler might be able to see that your pointers overlap, but if you had declared it char* data, it could have given bugs.

But, the strict-aliasing rule says that a char* and void* can point at any type. So you can rewrite it into:

double data;
...
*(((char*)&data) + i) = fgetc(stream);
...
return data;

Strict aliasing warnings are really important to understand or fix. They cause the kinds of bugs that are impossible to reproduce in-house because they occur only on one particular compiler on one particular operating system on one particular machine and only on full-moon and once a year, etc.

It looks a lot as if you really want to use fread:

int data;
fread(&data, sizeof(data), 1, stream);

That said, if you do want to go the route of reading chars, then reinterpreting them as an int, the safe way to do it in C (but not in C++) is to use a union:

union
{
    char theChars[4];
    int theInt;
} myunion;

for(int i=0; i<4; i++)
    myunion.theChars[i] = fgetc(stream);
return myunion.theInt;

I'm not sure why the length of data in your original code is 3. I assume you wanted 4 bytes; at least I don't know of any systems where an int is 3 bytes.

Note that both your code and mine are highly non-portable.

Edit: If you want to read ints of various lengths from a file, portably, try something like this:

unsigned result=0;
for(int i=0; i<4; i++)
    result = (result << 8) | fgetc(stream);

(Note: In a real program, you would additionally want to test the return value of fgetc() against EOF.)

This reads a 4-byte unsigned from the file in little-endian format, regardless of what the endianness of the system is. It should work on just about any system where an unsigned is at least 4 bytes.

If you want to be endian-neutral, don't use pointers or unions; use bit-shifts instead.