Question
getaddrinfo and IPv6
I'm trying to understand what the getaddrinfo function returns :
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h>
#include <sys/socket.h>
#include <netdb.h>
int main (int argc, char *argv[])
{
struct addrinfo *res = 0 ;
getaddrinfo("localhost", NULL ,NULL,&res);
printf("ai_flags -> %i\n", res->ai_flags) ;
printf("ai_family -> %i\n", res->ai_family) ;
printf("ai_socktype -> %i\n", res->ai_socktype) ;
printf("ai_protocol -> %i\n", res->ai_protocol) ;
printf("ai_addrlen -> %i\n", res->ai_addrlen) ;
struct sockaddr_in* saddr = (struct sockaddr_in*)res->ai_addr;
printf("ai_addr hostname -> %s\n", inet_ntoa(saddr->sin_addr));
freeaddrinfo(res);
return 0 ;
}
results :
ai_flags -> 40
ai_family -> 2
ai_socktype -> 1
ai_protocol -> 6
ai_addrlen -> 16
ai_addr hostname -> 127.0.0.1
In /etc/hosts, I 've got :
127.0.0.1 localhost
::1 localhost
Getaddrinfo returns only 127.0.0.1 and not ::1 ? I don't understand why ?
The second question is where can I find the meaning of those ints (40,2,1,6 etc) ? I've read the man but there is nothing about that.
I also wanted to know if it's possible to give a IPv6 adress (for example ::1) and the function returns the name : localhost ?
Thanks a lot !!