Question

How to test randomness (case in point - Shuffling)

First off, this question is ripped out from this question. I did it because I think this part is bigger than a sub-part of a longer question. If it offends, please pardon me.

Assume that you have a algorithm that generates randomness. Now how do you test it? Or to be more direct - Assume you have an algorithm that shuffles a deck of cards, how do you test that it's a perfectly random algorithm?

To add some theory to the problem - A deck of cards can be shuffled in 52! (52 factorial) different ways. Take a deck of cards, shuffle it by hand and write down the order of all cards. What is the probability that you would have gotten exactly that shuffle? Answer: 1 / 52!.

What is the chance that you, after shuffling, will get A, K, Q, J ... of each suit in a sequence? Answer 1 / 52!

So, just shuffling once and looking at the result will give you absolutely no information about your shuffling algorithms randomness. Twice and you have more information, Three even more...

How would you black box test a shuffling algorithm for randomness?

 47  15894  47
1 Jan 1970

Solution

 30

Statistics. The de facto standard for testing RNGs is the Diehard suite (originally available at http://stat.fsu.edu/pub/diehard). Alternatively, the Ent program provides tests that are simpler to interpret but less comprehensive.

As for shuffling algorithms, use a well-known algorithm such as Fisher-Yates (a.k.a "Knuth Shuffle"). The shuffle will be uniformly random so long as the underlying RNG is uniformly random. If you are using Java, this algorithm is available in the standard library (see Collections.shuffle).

It probably doesn't matter for most applications, but be aware that most RNGs do not provide sufficient degrees of freedom to produce every possible permutation of a 52-card deck (explained here).

2008-09-11

Solution

 7

Here's one simple check that you can perform. It uses generated random numbers to estimate Pi. It's not proof of randomness, but poor RNGs typically don't do well on it (they will return something like 2.5 or 3.8 rather ~3.14).

Ideally this would be just one of many tests that you would run to check randomness.

Something else that you can check is the standard deviation of the output. The expected standard deviation for a uniformly distributed population of values in the range 0..n approaches n/sqrt(12).

/**
 * This is a rudimentary check to ensure that the output of a given RNG
 * is approximately uniformly distributed.  If the RNG output is not
 * uniformly distributed, this method will return a poor estimate for the
 * value of pi.
 * @param rng The RNG to test.
 * @param iterations The number of random points to generate for use in the
 * calculation.  This value needs to be sufficiently large in order to
 * produce a reasonably accurate result (assuming the RNG is uniform).
 * Less than 10,000 is not particularly useful.  100,000 should be sufficient.
 * @return An approximation of pi generated using the provided RNG.
 */
public static double calculateMonteCarloValueForPi(Random rng,
                                                   int iterations)
{
    // Assumes a quadrant of a circle of radius 1, bounded by a box with
    // sides of length 1.  The area of the square is therefore 1 square unit
    // and the area of the quadrant is (pi * r^2) / 4.
    int totalInsideQuadrant = 0;
    // Generate the specified number of random points and count how many fall
    // within the quadrant and how many do not.  We expect the number of points
    // in the quadrant (expressed as a fraction of the total number of points)
    // to be pi/4.  Therefore pi = 4 * ratio.
    for (int i = 0; i < iterations; i++)
    {
        double x = rng.nextDouble();
        double y = rng.nextDouble();
        if (isInQuadrant(x, y))
        {
            ++totalInsideQuadrant;
        }
    }
    // From these figures we can deduce an approximate value for Pi.
    return 4 * ((double) totalInsideQuadrant / iterations);
}

/**
 * Uses Pythagoras' theorem to determine whether the specified coordinates
 * fall within the area of the quadrant of a circle of radius 1 that is
 * centered on the origin.
 * @param x The x-coordinate of the point (must be between 0 and 1).
 * @param y The y-coordinate of the point (must be between 0 and 1).
 * @return True if the point is within the quadrant, false otherwise.
 */
private static boolean isInQuadrant(double x, double y)
{
    double distance = Math.sqrt((x * x) + (y * y));
    return distance <= 1;
}
2008-09-11