Question

Loop inside React JSX

I'm trying to do something like the following in React JSX (where ObjectRow is a separate component):

<tbody>
    for (var i=0; i < numrows; i++) {
        <ObjectRow/>
    } 
</tbody>

I realize and understand why this isn't valid JSX, since JSX maps to function calls. However, coming from template land and being new to JSX, I am unsure how I would achieve the above (adding a component multiple times).

 2054  2069378  2054
1 Jan 1970

Solution

 1808

Think of it like you're just calling JavaScript functions. You can't use a for loop where the arguments to a function call would go:

return tbody(
    for (let i = 0; i < numrows; i++) {
        ObjectRow()
    } 
)

See how the function tbody is being passed a for loop as an argument – leading to a syntax error.

But you can make an array, and then pass that in as an argument:

const rows = [];
for (let i = 0; i < numrows; i++) {
    rows.push(ObjectRow());
}
return tbody(rows);

You can basically use the same structure when working with JSX:

const rows = [];
for (let i = 0; i < numrows; i++) {
    // note: we are adding a key prop here to allow react to uniquely identify each
    // element in this array. see: https://reactjs.org/docs/lists-and-keys.html
    rows.push(<ObjectRow key={i} />);
}
return <tbody>{rows}</tbody>;

Incidentally, my JavaScript example is almost exactly what that example of JSX transforms into. Play around with Babel REPL to get a feel for how JSX works.

2014-04-05
Sophie Alpert

Solution

 1178

I am not sure if this will work for your situation, but often map is a good answer.

If this was your code with the for loop:

<tbody>
    for (var i=0; i < objects.length; i++) {
        <ObjectRow obj={objects[i]} key={i}>
    }
</tbody>

You could write it like this with map:

<tbody>
    {objects.map(function(object, i){
        return <ObjectRow obj={object} key={i} />;
    })}
</tbody>

ES6 syntax:

<tbody>
    {objects.map((object, i) => <ObjectRow obj={object} key={i} />)}
</tbody>
2014-04-05
Brigand

Solution

 749

If you don't already have an array to map() like @FakeRainBrigand's answer, and want to inline this so the source layout corresponds to the output closer than @SophieAlpert's answer:

With ES2015 (ES6) syntax (spread and arrow functions)

http://plnkr.co/edit/mfqFWODVy8dKQQOkIEGV?p=preview

<tbody>
  {[...Array(10)].map((x, i) =>
    <ObjectRow key={i} />
  )}
</tbody>

Re: transpiling with Babel, its caveats page says that Array.from is required for spread, but at present (v5.8.23) that does not seem to be the case when spreading an actual Array. I have a documentation issue open to clarify that. But use at your own risk or polyfill.

Vanilla ES5

Array.apply

<tbody>
  {Array.apply(0, Array(10)).map(function (x, i) {
    return <ObjectRow key={i} />;
  })}
</tbody>

Inline IIFE

http://plnkr.co/edit/4kQjdTzd4w69g8Suu2hT?p=preview

<tbody>
  {(function (rows, i, len) {
    while (++i <= len) {
      rows.push(<ObjectRow key={i} />)
    }
    return rows;
  })([], 0, 10)}
</tbody>

Combination of techniques from other answers

Keep the source layout corresponding to the output, but make the inlined part more compact:

render: function () {
  var rows = [], i = 0, len = 10;
  while (++i <= len) rows.push(i);

  return (
    <tbody>
      {rows.map(function (i) {
        return <ObjectRow key={i} index={i} />;
      })}
    </tbody>
  );
}

With ES2015 syntax & Array methods

With Array.prototype.fill you could do this as an alternative to using spread as illustrated above:

<tbody>
  {Array(10).fill(1).map((el, i) =>
    <ObjectRow key={i} />
  )}
</tbody>

(I think you could actually omit any argument to fill(), but I'm not 100% on that.) Thanks to @FakeRainBrigand for correcting my mistake in an earlier version of the fill() solution (see revisions).

key

In all cases the key attr alleviates a warning with the development build, but isn't accessible in the child. You can pass an extra attr if you want the index available in the child. See Lists and Keys for discussion.

2015-04-14
JMM

Solution

 141

Simply using map Array method with ES6 syntax:

<tbody>
  {items.map(item => <ObjectRow key={item.id} name={item.name} />)} 
</tbody>

Don't forget the key property.

2016-10-30
danielfeelfine

Solution

 115

Using the Array map function is a very common way to loop through an Array of elements and create components according to them in React. This is a great way to do a loop which is a pretty efficient and is a tidy way to do your loops in JSX. It's not the only way to do it, but the preferred way.

Also, don't forget having a unique Key for each iteration as required. The map function creates a unique index from 0, but it's not recommended using the produced index, but if your value is unique or if there is a unique key, you can use them:

<tbody>
  {numrows.map(x=> <ObjectRow key={x.id} />)}
</tbody>

Also, a few lines from MDN if you not familiar with the map function on Array:

map calls a provided callback function once for each element in an array, in order, and constructs a new array from the results. callback is invoked only for indexes of the array which have assigned values, including undefined. It is not called for missing elements of the array (that is, indexes that have never been set, which have been deleted or which have never been assigned a value).

callback is invoked with three arguments: the value of the element, the index of the element, and the Array object being traversed.

If a thisArg parameter is provided to the map, it will be used as callback's this value. Otherwise, the value undefined will be used as its this value. This value ultimately observable by the callback is determined according to the usual rules for determining the this seen by a function.

map does not mutate the array on which it is called (although callback, if invoked, may do so).

2017-05-16
Alireza

Solution

 89

If you're already using lodash, the _.times function is handy.

import React, { Component } from "react";
import Select from "./Select";
import _ from "lodash";

export default class App extends Component {
  render() {
    return (
      <div className="container">
        <ol>
          {_.times(3, (i) => (
            <li key={i}>repeated 3 times</li>
          ))}
        </ol>
      </div>
    );
  }
}
2015-10-05
mpen

Solution

 85

There are multiple ways to go about doing this. JSX eventually gets compiled to JavaScript, so as long as you're writing valid JavaScript, you'll be good.

My answer aims to consolidate all the wonderful ways already presented here:

If you do not have an array of object, simply the number of rows:

Within the return block, creating an Array and using Array.prototype.map:

render() {
  return (
    <tbody>
      {Array(numrows).fill(null).map((value, index) => (
        <ObjectRow key={index}>
      ))}
    </tbody>
  );
}

Outside the return block, simply use a normal JavaScript for loop:

render() {
  let rows = [];
  for (let i = 0; i < numrows; i++) {
    rows.push(<ObjectRow key={i}/>);
  }
  return (
    <tbody>{rows}</tbody>
  );
}

Immediately invoked function expression:

render() {
  return (
    <tbody>
      {(() => {
        let rows = [];
        for (let i = 0; i < numrows; i++) {
          rows.push(<ObjectRow key={i}/>);
        }
        return rows;
      })()}
    </tbody>
  );
}

If you have an array of objects

Within the return block, .map() each object to a <ObjectRow> component:

render() {
  return (
    <tbody>
      {objectRows.map((row, index) => (
        <ObjectRow key={index} data={row} />
      ))}
    </tbody>
  );
}

Outside the return block, simply use a normal JavaScript for loop:

render() {
  let rows = [];
  for (let i = 0; i < objectRows.length; i++) {
    rows.push(<ObjectRow key={i} data={objectRows[i]} />);
  }
  return (
    <tbody>{rows}</tbody>
  );
}

Immediately invoked function expression:

render() {
  return (
    <tbody>
      {(() => {
        const rows = [];
        for (let i = 0; i < objectRows.length; i++) {
          rows.push(<ObjectRow key={i} data={objectRows[i]} />);
        }
        return rows;
      })()}
    </tbody>
  );
}
2017-06-02
Yangshun Tay

Solution

 57

You can also extract outside the return block:

render: function() {
    var rows = [];
    for (var i = 0; i < numrows; i++) {
        rows.push(<ObjectRow key={i}/>);
    } 

    return (<tbody>{rows}</tbody>);
}
2016-01-04
Brandon Sibeitokgong

Solution

 48

You might want to checkout React Templates, which does let you use JSX-style templates in React, with a few directives (such as rt-repeat).

Your example, if you used react-templates, would be:

<tbody>
    <ObjectRow rt-repeat="obj in objects"/>
</tbody>
2015-02-02
Etai

Solution

 47

If you opt to convert this inside return() of the render method, the easiest option would be using the map( ) method. Map your array into JSX syntax using the map() function, as shown below (ES6 syntax is used).


Inside the parent component:

<tbody>
   { objectArray.map(object => <ObjectRow key={object.id} object={object.value} />) }
</tbody>

Please note the key attribute is added to your child component. If you didn't provide a key attribute, you can see the following warning on your console.

Warning: Each child in an array or iterator should have a unique "key" prop.

Note: One common mistake people do is using index as the key when iterating. Using index of the element as a key is an antipattern, and you can read more about it here. In short, if it's not a static list, never use index as the key.


Now at the ObjectRow component, you can access the object from its properties.

Inside the ObjectRow component

const { object } = this.props

Or

const object = this.props.object

This should fetch you the object you passed from the parent component to the variable object in the ObjectRow component. Now you can spit out the values in that object according to your purpose.


References:

map() method in JavaScript

ECMAScript 6 or ES6

2016-11-21
bharadhwaj

Solution

 39

If numrows is an array, it's very simple:

<tbody>
   {numrows.map(item => <ObjectRow />)}
</tbody>

The array data type in React is much better. An array can back a new array, and support filter, reduce, etc.

2017-01-11
lulin

Solution

 36

This can be done in multiple ways.

  1. As suggested above, before return store all elements in the array

  2. Loop inside return

    Method 1:

    let container = [];
    let arr = [1, 2, 3] //can be anything array, object
    arr.forEach((val, index) => {
      container.push(
      <div key={index}>
        val
      </div>)
      /**
      * 1. All loop generated elements require a key
      * 2. only one parent element can be placed in Array
      * e.g. container.push(
      *         <div key={index}>
                  val
                </div>
                <div>
                this will throw error
                </div>
            )
      **/
    });
    return (
      <div>
        <div>any things goes here</div>
        <div>{container}</div>
      </div>
    )
    

    Method 2:

    return (
      <div>
        <div>any things goes here</div>
        <div>
          {
            (() => {
              let container = [];
              let arr = [1, 2, 3] //can be anything array, object
              arr.forEach((val, index) => {
                container.push(
                  <div key={index}>
                    val
                  </div>)
              });
              return container;
            })()
          }
        </div>
      </div>
    )
    
2016-06-02
abhirathore2006

Solution

 33

There are several answers pointing to using the map statement. Here is a complete example using an iterator within the FeatureList component to list Feature components based on a JSON data structure called features.

const FeatureList = ({ features, onClickFeature, onClickLikes }) => (
  <div className="feature-list">
    {features.map(feature =>
      <Feature
        key={feature.id}
        {...feature}
        onClickFeature={() => onClickFeature(feature.id)}
        onClickLikes={() => onClickLikes(feature.id)}
      />
    )}
  </div>
); 

You can view the complete FeatureList code on GitHub. The features fixture is listed here.

2016-05-29
Manav Sehgal

Solution

 33

Let us say we have an array of items in your state:

[{name: "item1", id: 1}, {name: "item2", id: 2}, {name: "item3", id: 3}]

<tbody>
    {this.state.items.map((item) => {
        <ObjectRow key={item.id} name={item.name} />
    })}
</tbody>
2016-08-20
JFAP

Solution

 33

To loop for a number of times and return, you can achieve it with the help of from and map:

<tbody>
  {
    Array.from(Array(i)).map(() => <ObjectRow />)
  }
</tbody>

where i = number of times


If you want to assign unique key IDs into the rendered components, you can use React.Children.toArray as proposed in the React documentation

React.Children.toArray

Returns the children opaque data structure as a flat array with keys assigned to each child. Useful if you want to manipulate collections of children in your render methods, especially if you want to reorder or slice this.props.children before passing it down.

Note:

React.Children.toArray() changes keys to preserve the semantics of nested arrays when flattening lists of children. That is, toArray prefixes each key in the returned array so that each element’s key is scoped to the input array containing it.

<tbody>
  {
    React.Children.toArray(
      Array.from(Array(i)).map(() => <ObjectRow />)
    )
  }
</tbody>
2018-07-14
Jee Mok

Solution

 29

An ECMAScript 2015 / Babel possibility is using a generator function to create an array of JSX:

function* jsxLoop(times, callback)
{
    for(var i = 0; i < times; ++i)
        yield callback(i);
}

...

<tbody>
    {[...jsxLoop(numrows, i =>
        <ObjectRow key={i}/>
    )]}
</tbody>
2016-12-28
David Hogan

Solution

 24

ES2015 Array.from with the map function + key

If you have nothing to .map() you can use Array.from() with the map function to repeat elements:

<tbody>
  {Array.from({ length: 5 }, (value, key) => <ObjectRow key={key} />)}
</tbody>
2017-10-27
Do Async

Solution

 21

...Or you can also prepare an array of objects and map it to a function to have the desired output. I prefer this, because it helps me to maintain the good practice of coding with no logic inside the return of render.

render() {
const mapItem = [];
for(let i =0;i<item.length;i++) 
  mapItem.push(i);
const singleItem => (item, index) {
 // item the single item in the array 
 // the index of the item in the array
 // can implement any logic here
 return (
  <ObjectRow/>
)

}
  return(
   <tbody>{mapItem.map(singleItem)}</tbody>
  )
}
2016-05-21
Rafi Ud Daula Refat

Solution

 21

I use this:

gridItems = this.state.applications.map(app =>
          <ApplicationItem key={app.Id} app={app } />
);

PS: never forget the key or you will have a lot of warnings!

2017-01-25
J C

Solution

 19

Here's a simple solution to it.

var Object_rows = [];
for (var i = 0; i < numrows; i++) {
  Object_rows.push(<ObjectRow />);
}
<tbody>{Object_rows}</tbody>;

No mapping and complex code is required. You just need to push the rows to the array and return the values to render it.

2016-12-02
Javasamurai

Solution

 18

You can of course solve with a .map as suggested by the other answer. If you already use Babel, you could think about using jsx-control-statements.

They require a little of setting, but I think it's worth in terms of readability (especially for non-React developer). If you use a linter, there's also eslint-plugin-jsx-control-statements.

2016-09-26
Jurgo Boemo

Solution

 18

Simply use .map() to loop through your collection and return <ObjectRow> items with props from each iteration.

Assuming objects is an array somewhere...

<tbody>
  { objects.map((obj, index) => <ObjectRow obj={ obj } key={ index }/> ) }
</tbody>
2017-05-27
Joshua Michael Calafell

Solution

 17

Your JSX code will compile into pure JavaScript code, any tags will be replaced by ReactElement objects. In JavaScript, you cannot call a function multiple times to collect their returned variables.

It is illegal, the only way is to use an array to store the function returned variables.

Or you can use Array.prototype.map which is available since JavaScript ES5 to handle this situation.

Maybe we can write other compiler to recreate a new JSX syntax to implement a repeat function just like Angular's ng-repeat.

2015-06-26
hlissnake

Solution

 16

I tend to favor an approach where programming logic happens outside the return value of render. This helps keep what is actually rendered easy to grok.

So I'd probably do something like:

import _ from 'lodash';

...

const TableBody = ({ objects }) => {
  const objectRows = objects.map(obj => <ObjectRow object={obj} />);      

  return <tbody>{objectRows}</tbody>;
} 

Admittedly this is such a small amount of code that inlining it might work fine.

2016-04-01
Adam Donahue

Solution

 15

Here is a sample from the React documentation, JavaScript Expressions as Children:

function Item(props) {
  return <li>{props.message}</li>;
}

function TodoList() {
  const todos = ['finish doc', 'submit pr', 'nag dan to review'];
  return (
    <ul>
      {todos.map((message) => <Item key={message} message={message} />)}
    </ul>
  );
}

As for your case, I suggest writing like this:

function render() {
  return (
    <tbody>
      {numrows.map((roe, index) => <ObjectRow key={index} />)}
    </tbody>
  );
}

Please notice the key is very important, because React use the key to differ data in array.

2017-05-28
Sinka Lee

Solution

 15

You may use .map() in a React for loop.

<tbody>
    { newArray.map(() => <ObjectRow />) }
</tbody>
2021-07-15
Ali Raza

Solution

 13

Since you are writing JavaScript syntax inside JSX code, you need to wrap your JavaScript code in curly braces.

row = () => {
   var rows = [];
   for (let i = 0; i<numrows; i++) {
       rows.push(<ObjectRow/>);
   }
   return rows;
}
<tbody>
{this.row()}
</tbody>
2017-01-21
Rohit Jindal

Solution

 12

With time, the language is becoming more mature, and we often stumble upon common problems like this. The problem is to loop a Component 'n' times.

{[...new Array(n)].map((item, index) => <MyComponent key={index} />)}

where, n -is the number of times you want to loop. item will be undefined and index will be as usual. Also, ESLint discourages using an array index as key.

But you have the advantage of not requiring to initialize the array before and most importantly avoiding the for loop...

To avoid the inconvenience of item as undefined you can use an _, so that it will be ignored when linting and won't throw any linting error, such as

{[...new Array(n)].map((_, index) => <MyComponent key={index} />)}
2019-10-15
pope_maverick

Solution

 12

If you really want a for loop equivalent (you have a single number, not an array), just use range from Lodash.

Don't reinvent the wheel and don't obfuscate your code. Just use the standard utility library.

import range from 'lodash/range'

range(4);
// => [0, 1, 2, 3]

range(1, 5);
// => [1, 2, 3, 4]
2021-05-02
Dart Dega

Solution

 11

I use it like

<tbody>
  { numrows ? (
     numrows.map(obj => { return <ObjectRow /> }) 
    ) : null
  }
</tbody>
2017-04-18
Sampath