Question

Pointers and arrays in Python ctypes

I have a DLL containing a C function with a prototype like this:

int c_read_block(uint32 addr, uint32 *buf, uint32 num);

I want to call it from Python using ctypes. The function expects a pointer to a chunk of memory, into which it will write the results. I don't know how to construct and pass such a chunk of memory. The ctypes documentation isn't much help.

Constructing an array and passing it "byref", like this:

    cresult = (c_ulong * num)()
    err = self.c_read_block(addr, byref(cresult), num)

Gives this error message:

ArgumentError: argument 3: <type 'exceptions.TypeError'>: expected LP_c_ulong instance instead of pointer to c_ulong_Array_2

I guess that is because the Python ulong array is nothing like a c uint32 array. Should I use create_char_string. If so, how do I persuade Python to "cast" that buffer to an LP_c_ulong?

 45  83364  45
1 Jan 1970

Solution

 68

You can cast with the cast function :)

>>> import ctypes
>>> x = (ctypes.c_ulong*5)()
>>> x
<__main__.c_ulong_Array_5 object at 0x00C2DB20>
>>> ctypes.cast(x, ctypes.POINTER(ctypes.c_ulong))
<__main__.LP_c_ulong object at 0x0119FD00>
>>> 
2009-09-01

Solution

 4

You can cast the result, but ctypes allows you to use an array in place of a pointer, directly. The issue is the byref in your code (which would be the equivalent of a pointer to a pointer):

So instead of:

cresult = (c_ulong * num)()
err = self.c_read_block(addr, byref(cresult), num)

try:

cresult = (c_ulong * num)()
err = self.c_read_block(addr, cresult, num)
2018-08-24