Yeah this is referred to as a default parameter
Default function parameters allow formal parameters to be initialized with default values if no value or undefined is passed.
Syntax:
function [name]([param1[ = defaultValue1 ][, ..., paramN[ = defaultValueN ]]]) {
statements
}
Description:
Parameters of functions default to undefined However, in situations it might be useful to set a different default value. This is where default parameters can help.
In the past, the general strategy for setting defaults was to test parameter values in the body of the function and assign a value if they are undefined. If no value is provided in the call, its value would be undefined. You would have to set a conditional check to make sure the parameter is not undefined
With default parameters in ES2015, the check in the function body is no longer necessary. Now you can simply put a default value in the function head.
Example of the differences:
// OLD METHOD
function multiply(a, b) {
b = (typeof b !== 'undefined') ? b : 1;
return a * b;
}
multiply(5, 2); // 10
multiply(5, 1); // 5
multiply(5); // 5
// NEW METHOD
function multiply(a, b = 1) {
return a * b;
}
multiply(5, 2); // 10
multiply(5, 1); // 5
multiply(5); // 5
Different Syntax Examples:
Padding undefined vs other falsy values:
Even if the value is set explicitly when calling, the value of the num argument is the default one.
function test(num = 1) {
console.log(typeof num);
}
test(); // 'number' (num is set to 1)
test(undefined); // 'number' (num is set to 1 too)
// test with other falsy values:
test(''); // 'string' (num is set to '')
test(null); // 'object' (num is set to null)
Evaluated at call time:
The default argument gets evaluated at call time, so unlike some other languages, a new object is created each time the function is called.
function append(value, array = []) {
array.push(value);
return array;
}
append(1); //[1]
append(2); //[2], not [1, 2]
// This even applies to functions and variables
function callSomething(thing = something()) {
return thing;
}
function something() {
return 'sth';
}
callSomething(); //sth
Default parameters are available to later default parameters:
Params already encountered are available to later default parameters
function singularAutoPlural(singular, plural = singular + 's',
rallyingCry = plural + ' ATTACK!!!') {
return [singular, plural, rallyingCry];
}
//["Gecko","Geckos", "Geckos ATTACK!!!"]
singularAutoPlural('Gecko');
//["Fox","Foxes", "Foxes ATTACK!!!"]
singularAutoPlural('Fox', 'Foxes');
//["Deer", "Deer", "Deer ... change."]
singularAutoPlural('Deer', 'Deer', 'Deer peaceably and respectfully \ petition the government for positive change.')
Functions defined inside function body:
Introduced in Gecko 33 (Firefox 33 / Thunderbird 33 / SeaMonkey 2.30). Functions declared in the function body cannot be referred inside default parameters and throw a ReferenceError (currently a TypeError in SpiderMonkey, see bug 1022967). Default parameters are always executed first, function declarations inside the function body evaluate afterwards.
// Doesn't work! Throws ReferenceError.
function f(a = go()) {
function go() { return ':P'; }
}
Parameters without defaults after default parameters:
Prior to Gecko 26 (Firefox 26 / Thunderbird 26 / SeaMonkey 2.23 / Firefox OS 1.2), the following code resulted in a SyntaxError. This has been fixed in bug 777060 and works as expected in later versions. Parameters are still set left-to-right, overwriting default parameters even if there are later parameters without defaults.
function f(x = 1, y) {
return [x, y];
}
f(); // [1, undefined]
f(2); // [2, undefined]
Destructured paramet with default value assignment:
You can use default value assignment with the destructuring assignment notation
function f([x, y] = [1, 2], {z: z} = {z: 3}) {
return x + y + z;
}
f(); // 6
